64121=(BC15.4)264 over 121 end-fraction equals open paren the fraction with numerator cap B cap C and denominator 15.4 end-fraction close paren squared 3. Calculate the ratio of sides

811=BC15.48 over 11 end-fraction equals the fraction with numerator cap B cap C and denominator 15.4 end-fraction 4. Solve for side BCcap B cap C Multiply both sides by to isolate BCcap B cap C

The length of side BCcap B cap C 1. Identify the relationship between areas and sides

import math area_abc = 64 area_def = 121 ef = 15.4 # Ratio of areas of similar triangles is equal to the square of the ratio of their corresponding sides. # (BC / EF)^2 = Area(ABC) / Area(DEF) # BC / EF = sqrt(Area(ABC) / Area(DEF)) bc = ef * math.sqrt(area_abc / area_def) print(f"{bc=}") Use code with caution. Copied to clipboard

Let О”abcв€јо”def And Their Areas Be Respectively 64cmві And 121cmві. If Ef=15.4cm Find Bc. Direct

64121=(BC15.4)264 over 121 end-fraction equals open paren the fraction with numerator cap B cap C and denominator 15.4 end-fraction close paren squared 3. Calculate the ratio of sides

811=BC15.48 over 11 end-fraction equals the fraction with numerator cap B cap C and denominator 15.4 end-fraction 4. Solve for side BCcap B cap C Multiply both sides by to isolate BCcap B cap C 64121=(BC15

The length of side BCcap B cap C 1. Identify the relationship between areas and sides Identify the relationship between areas and sides import

import math area_abc = 64 area_def = 121 ef = 15.4 # Ratio of areas of similar triangles is equal to the square of the ratio of their corresponding sides. # (BC / EF)^2 = Area(ABC) / Area(DEF) # BC / EF = sqrt(Area(ABC) / Area(DEF)) bc = ef * math.sqrt(area_abc / area_def) print(f"{bc=}") Use code with caution. Copied to clipboard 64121=(BC15