Gdz Po: Algebre Iu.n. Makarychev, N.g Mindiuk.k.i. Neshkov, S.b Suvorova

(x−3)(x+3)2(x+3)=x−32the fraction with numerator open paren x minus 3 close paren open paren x plus 3 close paren and denominator 2 open paren x plus 3 close paren end-fraction equals the fraction with numerator x minus 3 and denominator 2 end-fraction ✅ The simplified expression is

ГДЗ по алгебре за 7 класс, решебник и ответы онлайн

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x2−92x+6the fraction with numerator x squared minus 9 and denominator 2 x plus 6 end-fraction Use the difference of squares formula

x2−9=(x−3)(x+3)x squared minus 9 equals open paren x minus 3 close paren open paren x plus 3 close paren

2x+6=2(x+3)2 x plus 6 equals 2 open paren x plus 3 close paren

xv=−-42⋅1=42=2x sub v equals negative the fraction with numerator negative 4 and denominator 2 center dot 1 end-fraction equals four-halves equals 2 Plug back into the original equation:

Divide both the numerator and denominator by